What are the vertex and x intercepts of the graph of y=(x+4)(x-2)? Select one answer for the vertex and one for the x intercepts. A.x intercepts (-4,0) ,(2,0)B.x intercepts (-4,0)(-2,0)C.vertex (1,9)D.vertex (-1,-5)E.vertex (-1,-9)F.x intercepts (4,0),(-2,0)

Answer:The x-intercepts points are (-4 , 0) , (2 , 0) ⇒ answer (A)The vertex point is (-1 , -9) ⇒ answer (E)Step-by-step explanation:* Lets revise the quadratic equation  y = ax² + bx + c- To find the x-intercepts put y = 0- To find the vertex use the rule:# x-coordinate of the vertex of the parabola which represents   the quadratic function graphically = -b/2a# To find the y-coordinate substitute the value of the x-coordinate   of the vertex in the equation* Lets use these information to solve the problem∵ y = (x + 4)(x -2)- To find the x-intercepts let y = 0∴ (x + 4)( x - 2) = 0 ⇒ put each bracket = 0∴ x + 4 = 0 and x - 2 = 0∵ x + 4 = 0 ⇒ subtract 4 from the both sides∴ x = -4∵ x - 2 = 0 ⇒ add 2 to both sides∴ x = 2* The x-intercepts points are (-4 , 0) , (2 , 0)- Now lets use the foil method to multiply the two brackets∵ (x + 4)(x - 2) = x² - 2x + 4x - 8 ⇒ collect the like terms∴ (x + 4)(x - 2) = x² + 2x - 8∴ y = x² + 2x - 8* Now lets find the value of a and b to find the x-coordinate  of the vertex point∵ a = 1 , b = 2∵ x-coordinate of the vertex = -b/2a∴ x = -2/2(1) = -1- Substitute the value of x in y∴ y = (-1)² + 2(-1) - 8 = 1 - 2 - 8 = -9∴ The vertex point is (-1 , -9)* The vertex point is (-1 , -9)